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Find the dimensions of the rectangle of largest area that can be inscribed in an equilateral triangle of side length L if one side of the rectangle lies on the base of the triangle. List the dimensions in non-decreasing order (your answer may depend on L).

2 Answers

4 votes

Answer:

Base: L/2

Height: L * rad3 / 4

Explanation:

answered
User Jonathan Rowny
by
8.3k points
3 votes
Let the distance from the tip of the base of the triangle to the point that the top of the rectangle meets the triangle be x, then the width of the rectangle is √3/2x and the length of the rectangle is L - x.
Thus, Area of the rectangle = √3/2x(L - x) = √3/2xL - √3/2x^2
For maximum area, dA/dx = 0
dA/dx = √3/2L - √3x = 0
√3/2L = √3x
x = L/2
L - x = L - L/2 = L/2
√3/2x = √3/2(L/2) = √3/4L

Therefore, the dimensions of the square are L/2 and √3/4 L.
answered
User Gaoagong
by
8.1k points

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