Question

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle?

x2 + y2 − 6x − 16y + 48 = 0

x2 + y2 − 6x − 16y − 25 = 0

x2 + y2 + 6x + 16y + 48 = 0

x2 + y2 + 6x + 16y − 25 = 0

Answer 1

First we write equation that consist coordinates of center and radius. That formula goes like this:
(x-x1)^2 + (y-y1)^2 = r^2

x and y are coordinates on any point on circle
x1 and y1 are coordinates of center of circle.
r is radius of that circle. now we need to express our values for center and radius andf square binoms and see what matches in our options.

(x-3)^2 + (y-8)^2 = 5^2
x^2 + y^2 -6x -16y +48 = 0

The answer is first option.