Question

Suppose the definite integral, bottom value 2, top value 6 of g(x)dx=12 and the definite integral bottom value 5 top value 6 of g(x)dx= -3, find the value of the definite integral bottom value 2 and top value 5 of 3g(x)dx

Answer 1

The definite integral would be equal to your value from 2 to 6 minus your value from 5 to 6.

12 - (-3) = 15