A projectile is thrown upward so that its distance above the ground after t seconds is h(t)=-16t^2 + 570t. After how many seconds does it reach its maximum height?

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Sergey Kravchenko · Answer 1 · 2017-07-24T12:11:10+0000

It would only take 1 second to reach maximum height.

h(1)=−16(1^2)+(570)(1) after simplification, h would be 554.

If you kept increasing t, h would get smaller.

A projectile is thrown upward so that its distance above the ground after t seconds is h(t)=-16t^2 + 570t. After how many seconds does it reach its maximum height?

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A projectile is thrown upward so that its distance above the ground after t seconds is h(t)=-16t^2 + 570t. After how many seconds does it reach its maximum​ height?

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A projectile is thrown upward so that its distance above the ground after t seconds is h(t)=-16t^2 + 570t. After how many seconds does it reach its maximum height?