Question

HELP ME ASAP!! Some red white and blue candies were placed in a bowl. Some contain nuts, and some do not. Suppose one of the candies were chosen randomly from all the candies in the bowl. According to the table below, if the candy is blue, what is the probability that is does not contain any nuts?

Red with nuts=10. Red without nuts=10. White with nuts=20. White without nuts=10. Blue with nuts=20. Blue without nuts=30.
A. 20%
B. 40%
C. 60%
D. 10%

Answer 1

Answer: 20%

Explanation:

Answer 2

Option C: 60%

Explanation:

The number of blue candies with nuts = 20

The number of blue candies without nuts = 30

The total number of blue candies = 20 + 30 = 50

As the chosen candy is blue, the probability that is does not contain any nuts will be = (The number of blue candies without nuts)/(Total number of blue candies)

So, the probability = 30/50 = 0.6 *100% = 60%