Question

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g sucrose in 1.25L solution?

Answer 1

For the answer to the question above, use these formulas in solving your problem and as a guide.

MM = 342 (g/mol)

171 (g) / 342(g/mol) = x mol of sucrose
x moles of sucrose/ 1.25 L = Molarity of soultion

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