Question

The perimeters of a rectangle and an equilateral triangle are equal. The length of the rectangle is twice the width, and the side of the triangle is 8 more than the width of the rectangle. Which statements about this scenario are true if we use the variable w to represent the width of the rectangle?

Answer 1

The perimeter of triangle is 3(w+8) = 3w + 24

The perimeter of rectangle is w+w+2w+2w = 6w

Set them equal to solve for w:
6w = 3w +24
3w = 24
w = 8

Answer 2

for online school people it will be 2,3,4

Explanation:

i did the assigment