How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity

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asked Aug 6, 2017 217k views

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Margareth Reena · Answer 1 · 2017-08-10T12:10:00+0000

For small deflections, T = 2*pi*sqrt(L / g) where T is period, L is length and g is gravity. Setting the equations to the same period, 2*pi*sqrt(3.85 / g) = 2*pi*(L / (1/6 * g)) The equation reduces to 3.85 m = 6 * L so L = 0.642 m

How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity

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