asked 176k views
1 vote
Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

a. f(n + 1) = f(n) + 99.4, n ≥ 1
b. f(n + 1) = f(n) – 99.4, n ≥ 1
c. f(n + 1) = 99.4f(n), n ≥ 1
d. f(n + 1) = –99.4f(n), n ≥ 1

asked
User A Salim
by
7.6k points

1 Answer

7 votes
The correct answer is f(n+1)=f(n)-99.4, n≥1
I just completed the problem and it gave me the correct answer so I know this is right.
answered
User Yakuhzi
by
8.6k points
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