What is the boiling point and freezing point of a 2.21m AlCl3 aqueous solution? (the kf=1.86C/m and kb=0.512C/m)

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asked Apr 3, 2017 224k views

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Amiram Stark · Answer 1 · 2017-04-07T02:29:34+0000

ΔTb = i * Kb * m

ΔTb = 4 * 0.512 C/m * 2.21 m

solve DTb and add it to the BP of pure water

i get a new BP of 104.5 C and new FP of - 16.4 C

hope this helps

What is the boiling point and freezing point of a 2.21m AlCl3 aqueous solution? (the kf=1.86C/m and kb=0.512C/m)

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