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5 votes
how much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze?

asked
User GuilhE
by
8.2k points

1 Answer

5 votes
1 gallon of antifreeze = 60% of mixture. Total mixture:
Vm = 1/0.6
= 1.67 gallons

Volume of water = total vol - antifreeze vol
= 1.67 - 1
= 0.67 gallon of water
answered
User Rajax
by
8.7k points

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