Question

Find the derivative, y=t(lnt)^2, natural log=ln

Answer 1

hmm - i think thr answer is 2 ln t + (ln t)^2

Answer 2

`y=t(ln(t))^2 \\y'=[t(ln(t))^2]'=t'(ln(t))^2+t[(ln(t))^2]'=(ln(t))^2+2tln(t)(ln(t))'= \\ \\=(ln(t))^2+2t(1)/(t)ln(t) =(ln(t))^2+2ln(t) =ln(t)(ln(t)+2)`