Question

A boy throws a stone horizontally from the top of a cliff of height h = 50.0 m towards the

ocean below. The stone strikes the water at a distance d = 60.0 m from the base of the cliff.

The time at which the stone lands in the water is 3.19s. Calculate the initial speed of the stone?

Answer 1

The vertical component of the stone's initial velocity is 0 because it was projected horizontally.
The horizontal component:
velocity = displacement / time
Vx = 60 / 3.19
Vx = 18.8 m/s
V = Vx
So the stone's initial velocity is 18.8 m/s