asked 160k views
2 votes
If dy/dx = y cos x and y = 3 when x = 0, then y =....? Here are the answer choices

a) e^(sinx) +2
b) e^(sinx) + 3
c) sin x + 3
d) sin x + 3e^x
e) 3e^ (sinx)

1 Answer

3 votes
dy/dx = y cos x
y = Ae^sin(x)
y(0) = Ae^sin(0) = A = 3
A = 3

Therefore, y = 3e^(sinx)
answered
User Ben Flowers
by
8.3k points

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