Find equation of circle tangent to 3x-4y-4=0 at (0,-1) containing the point (-1,-8)

Question

asked Sep 18, 2017 30.5k views

1 Answer

Antony Thomas · Answer 1 · 2017-09-22T21:29:50+0000

i think I'm pretty sure that the center is the perpendicular bisector of the line joining (0, -1) and (-1 , -8)
So the equation would be :
(x-2) ^2 + (y+5) ^2 = 25

Hope this helps

Find equation of circle tangent to 3x-4y-4=0 at (0,-1) containing the point (-1,-8)

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions