Question

Convert the following complex number into its polar representation: 3i

Answer 1

Here I come with the picture for more proof, you can also check again by converting it back to the rectangular form

Answer 2

A) -3(cos0+isin0)
B) 3(cos pi+isin pi)
C) -3(cos3pi/2+isin 3pi/2)
D) 3(cos pi/2+isin pi/2)

The answer is D. It is obtained because,
`r= \sqrt{ 0.0^(2) + 3.0^(2) } = 3.0` and
`\alpha = arctan ( (3.0)/(0.0) ) = 90.0^(o)`

hence in polar form
`3(cos \frac{ \pi }2} + sin ( \pi )/(2)i)`