If you factor y^2-81 COMPLETELY, would it just be (y-9)(y+9), or would it be something like y(3)(-3)y(3)(3)?

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asked Dec 14, 2017 26.4k views

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Dinuda Yaggahavita · Answer 1 · 2017-12-18T08:20:13+0000

That would be (y - 9)(y +9). When two binomials are multiplied, the distributive property is applied. However, if the equation is y(3)(-3)y(3)(3), you just simply multiply them altogether. That would be -81y^2, which is not equivalent with y^2 - 81.

If you factor y^2-81 COMPLETELY, would it just be (y-9)(y+9), or would it be something like y(3)(-3)y(3)(3)?

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