½H2(g) + ½I2(g) → HI(g), ΔH = + 26 kJ/mole 117 kJ/mole + C(s) + 2S(s) → CS2(g) The temperature of the surroundings will:

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Macbirdie · Answer 1 · 2017-01-06T23:17:28+0000

Answer:

Increase

Step-by-step explanation:

The given equation is an example of an exothermic reaction. Hence heat is release in the surrounding and the temperature of the surrounding will increase.

½H2(g) + ½I2(g) → HI(g), ΔH = + 26 kJ/mole 117 kJ/mole + C(s) + 2S(s) → CS2(g) The temperature of the surroundings will:

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