Choose the quadratic equation with a leading coefficient of 1 that has as solutions √(3)+2i√(5) and √(3)-2i√(5)

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asked Oct 2, 2017 3.0k views

1 Answer

Milan · Answer 1 · 2017-10-08T13:09:58+0000

The quadratic equation for the given solution would be
(x−√3+2i√5)(x−√3−2i√5)
if you will expand it further you will get
x^2+x+5

and that will lead to the solution.

Choose the quadratic equation with a leading coefficient of 1 that has as solutions √(3)+2i√(5) and √(3)-2i√(5)

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