Question

consider the point (x,y) lying on the graph of y=(x+3)^1/2. let L be the distance between the points (x,y) and (4,0). write l as a function of y

Answer 1

`L=√( (x-4)^2 + y^2 )`
and

`<span>y=√(x+3) \Rightarrow x = y^2-3`


`L=√( (x-4)^2 + y^2 )=√( (y^2 - 3-4)^2 + y^2 )=√( (y^2-7)^2 + y^2 )`