Question

F(x)= 9-x^2, x ≥ 0. f^-1(x)=??

Answer 1

`y=9-x^(2),\ x\ge0`

Reverse
`x` and
`y`:

`x=9-y^(2),\ y\ge0`
Solve for
`y`:

`x=9-y^(2)`

`\rightarrow y^(2)=9-x`

`\rightarrow y=√(9-x)` since
`y\ge0`