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1. Determine the zeros of f(x) = x3 – 3x2 – 16x + 48? Somebody explain it please?:/

1. Determine the zeros of f(x) = x3 – 3x2 – 16x + 48? Somebody explain it please?:/
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3 votes
1. Determine the zeros of f(x) = x3 – 3x2 – 16x + 48? Somebody explain it please?:/

asked
User Anupa
by
7.5k points

1 Answer

2 votes

x^(2) - 3x^(2) - 16x + 48 = 0


x^(2) (x - 3) - 16(x - 3) = 0


(x - 3) ( x^(2) - 16) = 0


(x - 3) (x - 4) (x + 4) = 0


x = -4, 3, 4

The zeros are: -4, 3, 4
answered
User Unsym
by
8.3k points
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