Question

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem?
3n2 + 5 = 116
3n2 + 3n + 3 = 116
3n2 + 6n + 5 = 116

Answer 1

You are supposed to use the third option: 3n2 + 6n + 5 = 116.
Take a look at the attachment to see how I got that solution.
Hope it helps! :)