Question

How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal?

2 K + F2 ---> 2 KF

Show the work or explain somehow if possible por favor(: ...?

Answer 1

The balanced chemical reaction is written as:

2K + F2 ---> 2 KF

We are given the amount of potassium metal to be used in the reaction. This will be the starting point for the calculation. We do as follows:

23.5 g K ( 1 mol / 39.1 g ) ( 1 mol F2/2 mol K ) ( 22.4 L / 1 mol ) = 13.46 L F2