asked 49.3k views
2 votes
Determine whether the sequence:

ln(2n^2 +1) - ln(n^2 +1)

converges or diverges. If the sequence converges, find the limit.

asked
User Jpobst
by
8.3k points

1 Answer

7 votes

\\ \lim_(n \to \infty) ln( (2n^2+1) )-ln((n^2+1)) \\ \\ \lim_(n \to \infty) \ln{ (2n^2+1)/(n^2+1) } \\ \\ \lim_(n \to \infty) \ln{ ( (2n^2)/(n^2) + (1)/(n^2))/( (n^2)/(n^2)+ (1)/(n^2)) } \\ \\ \lim_(n \to \infty) \ln{ ( 2 + (1)/(n^2))/( 1+ (1)/(n^2)) } \\ \\ \ln{ ( 2 + 0)/( 1+ 0) } \\ \\ ln(2)
answered
User Knagode
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.