Question

What is the solution to the following bernoulli de?
\[t^2 dy/dx+y^2=ty\]

Answer 1

So, from your equation t^2 dy/dx+y^2=ty

Dividing boths side by t^2 we get
dy/dx+y^2/t^2=y/t
After re arranging

dy/dx−y/t=−y^2/t^2

after substituting we get
w=−y^−3