Question

If (3x^2)+7=0 then (x-1/3)^2

Answer 1

`3x^2+7=0 \\x^2=- (7)/(3) \\x=\pm \sqrt{-(7)/(3) } \\x=\pm i \sqrt{(7)/(3) } \\ \\(x- (1)/(3) )^2=x^2- (2)/(3)x+ (1)/(9) =- (7)/(3) -(2)/(3)(\pm i \sqrt{(7)/(3) } )+ (1)/(9) = \\=- (21)/(9) -(2)/(3)(\pm i \sqrt{(7)/(3) } )+ (1)/(9) \\=- (20)/(9) \mp i(2)/(3) \sqrt{(7)/(3) }`