asked 96.3k views
1 vote
In the game of roulette, a player can place a $4 bet on the number 22 and have a 1/38 probability of winning. If the metal ball lands on 22, the player gets to keep the $4 paid to play the game and the player is awarded $140. Otherwise, the player is awarded nothing and the casino takes the players $4. What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose? ...?

asked
User Dazz
by
9.1k points

1 Answer

3 votes
E= 140 (1/38) - 4 (37/38)
= -4/19
-0.21

0.21 x 1000 = $210
answered
User Ilkin
by
8.1k points
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