Prove the trigonometric identity: (csc^2x)/(cotx)=cscxsecx ...?

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asked Apr 21, 2017 45.0k views

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Sootah · Answer 1 · 2017-04-25T06:32:51+0000

cscx = 1 / sinx, so csc^2x = 1/ sin²x, and cotx=cosx / sinx
so (csc^2x)/(cotx)=(1/ sin²x) (sinx/cosx) = 1/(sinxcosx) = 1/sinx 1/cosx
finally
(csc^2x)/(cotx)=cscxsecx

Prove the trigonometric identity: (csc^2x)/(cotx)=cscxsecx ...?

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