Question

What is the value of the range of the function f(x) = x squared +2 for the domain value 1/4?

a.) y=2
b.) y=2 1/4
c.) y= 2 1/8
d.) y= 2 1/16

Answer 1

i think the answer is d

Answer 2

ur looking for the range...so u r looking for f(x) or y....and x = 1/4

f(x) = 1/4^2 + 2
f(1/4) = 1/4 * 1/4 + 2
f(1/4) = 1/8 + 2
f(1/4) = 1/8 + 16/8
f(1/4) = 17/8 which equals 2 1/8....so y = 2 1/8