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Why not when you have s+(sx)=60 divide by x to get s+s=60/x thus giving 2s=60/x and then s = 60/2x and thus 30 /x
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Why not when you have s+(sx)=60 divide by x to get s+s=60/x thus giving 2s=60/x and then s = 60/2x and thus 30 /x
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Sep 22, 2017
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Why not when you have s+(sx)=60 divide by x to get s+s=60/x thus giving 2s=60/x
and then s = 60/2x and thus 30 /x
Mathematics
college
Koxta
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well
s+sx=60
if you divided both sides by x (same as multiplying by 1/x) you would do
(1/x)(s+sx)=(1/x)60
s/x+sx/x=60/x
s/x=s=60
the division carries over to both terms
undistribute s
s(1+x)=60
divide both sides by 1+x
s=
Mark Molina
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Sep 24, 2017
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Mark Molina
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You can't do that, because what you do to one side you have to do to the other, and so, you have to divide the entire left side term by x, so you'd get:
s/x + s = 60/x not s+s=60/x
Mdakin
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Sep 26, 2017
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Mdakin
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