Question

How many moles of nacl are contained in 27.5ml of .105 m of nacl solution?

Answer 1

`2.9.10^(-3)` mol NaCl

Step-by-step explanation:

we have the following data

27.5 mL= Volumen

`1000 mL \longrightarrow 1 L\\ 27.5 mL \longrightarrow x\\\\x=(27.5)/(1000)\\ x= 0.0275 L`

Molarity is defined as moles of solute per liter of solution

0.105 M = Molarity

We know that there are 0.105 moles of NaCl per liter of solution

then how many moles of NaCl will be in 27.5 mL of solution

`1 L \longrightarrow 0.105 mol NaCl\\27.5.10^(-3)L \longrightarrow x\\x=((27.5.10^(-3))(0.105))/(1)= 2.9 . 10^(-3)mol NaCl`

Answer 2

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate as follows:

0.105 mol / L (.0275 L ) = 0.003 mol NaCl

Hope this answers the question. Have a nice day.