asked 127k views
5 votes
Solve the equation
x^2-12x+36=25

asked
User Hyelim
by
7.6k points

2 Answers

2 votes
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x = 11,1.
answered
User Dazfl
by
8.4k points
6 votes

Answer:

The answer are 11 and 1

Explanation:

Given the equation x²-12x+36 = 25, to solve the equation means calculating for all the possible value of the x variable. To get that, we will have to make x the subject of the formula;

Step 1: we will subtract 36 from both sides of the equation to have;

x²-12x+36-36 = 25-36

x²-12x = -11

2nd step: We will add 11 to both sides of the equation to have;

x²-12x+11 = 0

3rd step: we will factorise the resulting quadratic equation to have;

(x²-11x)-(x+11)=0

x(x-11)-1(x-11)= 0

(x-1)(x-11)= 0

x-1 =0 and x - 11 = 0

Step 3: we will calculate the possible values of x.

If x-1 =0, x= 1

If x-11 =0, x = 11

The possible values of x are 11 and 1

answered
User Dfb
by
8.1k points

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