Question

What is the equation of a line, in general form, that passes through points (-1, 2) and (5, 2)?

y - 2 = 0
x - 2 = 0
y - x - 2 = 0

Answer 1

(-1,2)(5,2)
notice how both ur sets of points have the same y value (2).... This means u have a horizontal line with a 0 slope. Ur equation would be y = 2....in general form, it would be : y - 2 = 0

Answer 2

we know that

the equation of the line in standard form is equal to

`Ax+By+C=0`

where

A,B and C are real numbers

In this problem we have

`A(-1,2)\ B(5,2)`

Find the slope of the line AB

The formula to calculate the slope is equal to

`m=(y2-y1)/(x2-x1)`

substitute the values

`m=(2-2)/(5+1)`

`m=(0)/(6)`

`m=0`

The line is parallel to the x-axis

The equation of the line is the y-coordinate of the points that passes through the line

`y=2`

Convert to general form

`y-2=0`

therefore

the answer is the option

`y-2=0`