asked 210k views
2 votes
Determine an appropriate solution to solve xdy/dx=yln(xy)

asked
User Tamtom
by
8.5k points

1 Answer

1 vote

x(\mathrm dy)/(\mathrm dx)=y\ln(xy)

Let
v=xy, so that
(\mathrm dv)/(\mathrm dx)=y+x(\mathrm dy)/(\mathrm dx), or
(\mathrm dv)/(\mathrm dx)-\frac vx=x(\mathrm dy)/(\mathrm dx). Then you have


(\mathrm dv)/(\mathrm dx)-\frac vx=\frac vx\ln v

(\mathrm dv)/(v(\ln v+1))=\frac{\mathrm dx}x

Integrate both sides to get


\ln|\ln v+1|=\ln|x|+C

\ln v+1=Cx

v=e^(Cx-1)

then back-substitute to find the solution for
y.


xy=e^(Cx-1)\implies y=\frac{e^(Cx-1)}x
answered
User Alex Tartan
by
9.3k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.