Question

Solve the system algebraically.
3x - 2y - 1 = 0 y = 5x + 4
What is the solution?

Answer 1

3x - 2 ( 5x + 4 ) - 1 = 0
3x - 10x - 8 - 1 = 0
7x = - 9
x = - 9/7

y = 5 ( - 9/7 ) + 4
y = - 45/7 + 4
y = - 3/45/7

Answer 2

`x=(-9)/(7)`

`y=(-17)/(7)`

Explanation:

We have been given the equation:

`3x-2y-1=0`

And
`y=5x+4`

Second equation can be rewritten as:

`5x-y=-4`

We will solve the equations:

`3x-2y=1` (1)

`5x-y=-4` (2)

Multiply equation (1) by 5 and equation (2) by 3 we get:

`15x-10y=5` (3)

`15x-3y=-12` (4)

Now, subtract (4) from (3) we get:

`-7y=17`

`y=(-17)/(7)`

Now substitute
`y=(-17)/(7)` in equation (1) we get:

`3x-2{(-17)/(7)}=1`

`3x+(34)/(7)=1`

`21x=-27`

`x=\frac[-27}{21}`

`x=(-9)/(7)`