Question

What is the 7th term of the geometric sequence where a1 = -625 and a2 = 125

Answer 1

r = 125 ÷ - 625
r = - 0.2

T7 = - 625(-0.2)^16
= - 625 × 0.2
= - 125

Answer 2

The 7th term of the geometric sequence where a1 = -625 and a2 = 125 is -125.

The solution would be like this for this specific problem:r = 125/-625
r = - 0.2

7th term= - 625(-0.2)^16
= - 625 × 0.2
= - 125I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.