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3 votes
Find the zero of y=x^2+6x-4 by completing the square

1 Answer

4 votes
x^2 + ( 6/2 )^2 - ( 6/2 )^2 - 4 = 0
( x + 3 )^2 - 3 - 4 = 0
( x + 3 )^2 - 7 = 0
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User Sbabbi
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