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Solve 4sin2θ + 4cosθ - 5 = 0 for 0° ≤ θ < 180°. Ø 0° 30° 60°

Solve 4sin2θ + 4cosθ - 5 = 0 for 0° ≤ θ < 180°. Ø 0° 30° 60°
asked 183k views
3 votes
Solve 4sin2θ + 4cosθ - 5 = 0 for 0° ≤ θ < 180°.
Ø
0°
30°
60°

asked
User MGZero
by
7.2k points

1 Answer

4 votes
the answer is 60 or 300
answered
User Gibatronic
by
8.2k points
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