Question

Write the standard form of the equation of the circle below.

Center (0,-1) passes through the point (-1,-2)

Answer 1

`x^2+(y+1)^2=2`

Explanation:

We use the formula for a circle with center at (0, -1), that goes through the (x, y) point (-1, -2):

`(x-0)^2 + (y-(-1))^2 = R^2\\Using \,\,\,point\,\,\,(-1, -2)\\(-1-0)^2+ (-2+1)^2 = 1 + 1 = 2 = R^2`

Therefore, the equation of this circle can be written as:

`x^2+(y+1)^2=2`