asked 43.1k views
16 votes
Find the zeros of 6x^2-27x

2 Answers

8 votes
x=9/2 is correct how wisdom said
answered
User Alveomaster
by
8.3k points
4 votes

Answer:

x = 0, 9/2

Explanation:

6x^2 - 27x = 0 (original)

3x(2x - 9) = 0 (factor out GCF of 3x)

|

v

(solve each factor (3x and 2x - 9) for x)

3x = 0

x = 0

2x - 9 = 0

2x = 9

x = 9/2

answered
User Jhole
by
8.3k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.