Question

Help please I really need it

Answer 1

So we want to solve 2x − 40 = 3y for x2x − 40 + 40 = 3y + 40(Add 40 to both sides!)2x = 3y + 40
Now divide both sides by 2!

`(2x)/(2) = (3y + 40)/(2) \ \textgreater \ x = (3)/(2)y + 20`
Now substitute
`(3)/(2)y + 20 for x in 2y = -4x + 48`

`2y = -4( (3)/(2)y + 20) + 48`
Which then gives us..
2y = −6y − 32(Make sure to simplify both sides of the equation)2y + 6y = −6y − 32 + 6y(Now add 6y to both sides)8y = −32
Now divide both sides by 8

`(8y)/(8) = (-32)/(8) \ \textgreater \ y = -4`
Now we have to substitute -4 for y in
`x = (3)/(2)y + 20 \ \textgreater \ (3)/(2)(-4) + 20 \ \textgreater \ x = 14`
So we end up getting...
x = 14 and y = −4.
Hope this helps!