Question

If a person burns 2171 Cal each day, how much energy (kJ) does she burn in 2 days??

Answer 1

As 1 calorie = 4.184 jouls

Or

1 calorie = 0.004184 kilojouls

Total calories for two days = 2171 x 2 = 4342 calories

Hence the energy in kj = 4342 x 0.004184 = 18.16 kj