Given the trinomial x^2-bx-c where both the first and the second signs are negative, the signs of the factors will be: A. cannot determine B. both negative C. both positive D. o…

Question

asked Feb 7, 2017 181k views

2 Answers

Tgrez · Answer 1 · 2017-02-12T17:56:15+0000

Answer: Option 'D' is correct.

Explanation:

Since we have given that

x^2-bx-c=0

Both the first and second signs are negative,

Let α and β are the roots of the
x^2-bx-c=0 ,

then, we know that the relationship between the zeroes and coefficients of quadratic equations:

$\alpha+\beta =(-b)/(a)=b\\\\and\\\\\alpha \beta =(-c)/(a)=-c$

Since the product of roots is positive.

So, the signs of the factors will be one positive and one negative.

Hence, Option 'D' is correct.