Question

A golfer hits a golf ball at an angle of 25.0° to the ground. If the golf ball

covers a horizontal distance of 301.5 m, what is the ball’s maximum
height? (Hint: At the top of its flight, the ball’s vertical velocity component will be zero.

Answer 1

To find the maximum height of the ball, we can use the kinematic equations of motion for projectile motion. The height of the ball can be calculated using the equation h = h0 + (v0^2 * sin^2(θ))/(2g). Given that the ball covers a horizontal distance of 301.5 m, we can calculate the initial speed of the ball and then substitute the values to find the maximum height.

Step-by-step explanation:

To find the maximum height of the ball, we can use the kinematic equations of motion for projectile motion. The vertical motion of the ball can be described by the equation:

h = h0 + v0yt - (1/2)gt2

Where:

• h is the height of the ball
• h0 is the initial height of the ball
• v0y is the vertical component of the initial velocity
• t is the time of flight
• g is the acceleration due to gravity

At the top of its flight, the ball's vertical velocity component will be zero. So, v0y can be determined using the equation:

v0y = v0sin(θ)

Where:

• v0 is the initial speed of the ball
• θ is the angle of projection

Once v0y is known, the time of flight can be determined using the equation:

t = 2v0y/g

Substituting the values into the equation for height, we can solve for h:

h = h0 + (v0sin(θ))(2v0sin(θ))/g - (1/2)g(2v0sin(θ)/g)2

Simplifying the equation:

h = h0 + (v02sin2(θ))/(2g)

Given that the ball covers a horizontal distance of 301.5 m, we can calculate the initial speed of the ball using the equation:

v0x = v0cos(θ)

v0x = 301.5 m / t

Once the initial speed is known, we can substitute the values into the equation for height to find the maximum height of the ball.

Answer 2

Please read the attached file