Question

If a certain shade of blue has a frequency of 7.33 x 10^14Hz, what is the energy of exactly one photon of this light?

Is this as simple as multiplying the frequency by Planck's constant?

Answer 1

The best way to express this is by means if this formula: E = h v. H is the plancks constant and v is the frequency. The procedure will look like this:
E = 6.626 x 10-34 J s (7.33 x 10^14 /s) = 4.857 x 10^-19 J
That is how we may express the energy. And as you can see, you can solve it with the plancks constant and multiplying the frequency