Question

What's the value of the product (3-2i)(3+2i)

Answer 1

We have to multiply given (3-2i)(3+2i)
(3-2i)(3+2i)=9-6i+6i+4i^2
9+4i^2
We know that i^2=-1, so lets substitute it
9+4*(-1)=9-4=5

Answer 2

the product (3-2i)(3+2i) is, 13

Explanation:

Using the identity rule:

`(a+b)(a-b) = a^2-b^2`

Given that:

`(3-2i)(3+2i)` ...[1]

here, i is the imaginary part.

`i^2 = -1`

Apply the rule on [1] we have;

`(3)^2-(2i)^2`

⇒
`9-(4i^2)`

⇒
`9+4`

Simplify:

13

Therefore, the product (3-2i)(3+2i) is, 13