What is the concentration of a Ca(OH)2 solution if 15.0 ml of 0.750 M H3PO4 solution is required to completely neutralize 20.0 ml of the Ca(OH)2 solution?

Question

asked Dec 23, 2017 158k views

2 Answers

Pnovotnak · Answer 1 · 2017-12-27T05:31:31+0000

Answer: The concentration of
comes out to be 0.843 M.

Step-by-step explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction

n_1M_1V_1=n_2M_2V_2

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is
H_3PO_4

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is
Ca(OH)_2

We are given:

$n_1=3\\M_1=0.75M\\V_1=15mL\\n_2=2\\M_2=?M\\V_2=20mL$

Putting values in above equation, we get:

$3* 0.750* 15=2* M_2* 20\\\\M_2=0.843M$

Hence, the concentration of
comes out to be 0.843 M.