What is the vertex of the quadratic function f(x)=(x-6)(x+2)

Question

asked Jan 12, 2017 13.3k views

2 Answers

Walter Gandarella · Answer 1 · 2017-01-18T04:03:49+0000

For this case we have the following function:

We rewrite the function making distributive property.

We have then:

To find the vertex of the function, we derive:

We equal zero and clear the value of x:

We evaluate the function for the value of x obtained:

Then, the vertice of the parabola is:

Answer:

the vertex of the quadratic function f(x)=(x-6)(x+2) is:

(x, y) = (2, -16)