Question

Find the distance from point S to line JP is S = (14, -6), J = (-2, 4), and P = (1, -9).

Please help.

Answer 1

i think is....
d=(−6−(14))2+(4−(−2))2+(−9−(1)^2

d=(−20)2+(6)2+(−10)2^2

d=400+36+100

d=5–√36d=536

d=23.151674